Sou still need this also for the provider in some way. Because if the threshold is 10k and you have 16k then you will get this 16k even the request says 36k (which was a part of the problem).

To still get multiple full train loads you simply can divide by T and then multiply by T. (Which was ...

mrvn wrote:But you are missing on the great opportunity to get 9000 copper plates and 27000 iron plates in a single train.

For me, that's a feature, not a bug. My stations only provide one thing, except for some stations which also provide empty barrels when they are done.

I have something which I think works. It basically limits to one train, but one train load per material, instead of one train for everything. The basic idea is you tell the circuit how many items fit onto a train load (signal T in the combinators), and no matter how many of anything you need, you ...

Only if multiple trains are set for the station.

Yeah, that's kind of critical for me. Especially on stations that have mixed deliveries.

You do not need to change the threshold.

Simply set the different thresholds behind different decider combinators.

Item 1 -> *Each <= -50k = *Each
Item 2 -> *Each <= -5k = *Each

This way the station will not see any request until it reaches your desired threshold. The only downside is the ...

I'm butting up against this too. I'd like to use the Roboport blueprint in the design thread, and have stations that can request a variety of materials, but like OP, I don't want to set the request threshold to be small and end up with half full trains of things with big stack sizes.

Is it possible ...

Thanks! That will help my testing, and it makes sense. I was looking for the slots on the wagon to be locked, but I am not sure why. That would not help with the left overs.

So just to make sure I am understanding correctly:

I use 8 wagon trains. Metal plates stack to 100, so my normal train full ...

So my understanding is that the locked slots per wagon setting is used when you have a provider that could provide more than one item. And it's designed to never fully fill a wagon, so stack inserters will always have room for their leftovers.

So my understanding is you put the signal to X slots at ...