Is there a way to make a Splitter place/split incoming items onto two belts in a 2:1 ratio (via circuits or something) , instead of its usual 1:1 ratio?
I tried the filter and input/output priority settings on the Splitter but they do not accomplish the simple & reliable 2:1 split.
Thanks for helping.
Can a Splitter place items in a 2:1 ratio?
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Bogdanov89
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Re: Can a Splitter place items in a 2:1 ratio?
Yes, you just need to split into 4 belts, then feed one belt back into the original splitter, like this.
(Obviously you can combine two of the belts to make it 2:1 instead of 1:1:1.)
(Obviously you can combine two of the belts to make it 2:1 instead of 1:1:1.)
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Re: Can a Splitter place items in a 2:1 ratio?
This is quite difficult for a pure mechanical solution, because splitters and splitter combinations just create ratios with powers of 2. Kyralessa's solution works only if the belt isn't stalling and all output is being consumed.
Here a solution that actively counts moved items and really makes sure every output belt gets its proper share. If you halt one output belt then release, it will catch up!
Right combinator; cast output belts to L and R, and with the outputs you define which ratio you want. In this case 2x R and 1x L as output defines a 1:2 ratio.
Left combinator; counter:
Here a solution that actively counts moved items and really makes sure every output belt gets its proper share. If you halt one output belt then release, it will catch up!
- 04-01-2026, 14-33-04.png (231.59 KiB) Viewed 238 times
- 04-01-2026, 14-33-44.png (57.75 KiB) Viewed 238 times
- 04-01-2026, 14-34-36.png (45.96 KiB) Viewed 238 times
- 04-01-2026, 14-41-03.png (72.65 KiB) Viewed 237 times
Re: Can a Splitter place items in a 2:1 ratio?
Which, to be fair, one could say about any purely mechanical splitting/balancing mechanism at any ratio.Tertius wrote: Wed Apr 01, 2026 12:39 pm Kyralessa's solution works only if the belt isn't stalling and all output is being consumed.